2. Studying moment of inertia and equivalent length of physical pendulum determination method.
3)Scheme of laboratory research facility:
1 physical pendulum;2 ruler;O pivot point;C center of gravity;leq equivalent length;α angle of deflection;a distance between pivot point (axis of rotation) and center of gravity; quasi-elastic force; supporting force; gravity force.
4)Table of measuring instruments:
Ή
Name
Type
Serial Ή
Grid limit
Grid unit
Absolute error
1.
Stopwatch
ΣXΛ-42
99,99 s
0,01 s
0,01 s
2.
Ruler
Σ
1000 mm
1mm
1mm
5) Equations for calculation:
1. Statistical absolute error for direct measurements of period:
,
where a = 0,95 confidence probability; n = 5 number of measurements; t 0,95 ; 5 = 2,77 Students coefficient.
Total absolute error of period
DT = ,
where DTDEV = 0,01s absolute instrumental error of stopwatch (see Table of measuring instruments).
2. Amplitude of oscillations
A= lsinα ≈ lα ,
here l length of a pendulum; a = 5O angle of deflection.
Cyclic eigenfrequency of oscillations
,
where <T> average value of period of oscillations.
Initial phase of oscillations:
j0 =p, when initial deflection to the left and x=x(t=0)= A;
j0 =0, when initial deflection to the right and x=x(t=0)= +A.
Equation of oscillations of physical pendulum:
x(t)=Acos(ω0t+φ0);
where x linear displacement of pendulum; t time.
3. Experimentally determined by indirect measurement an average value of moment of inertia:
,
where m mass of a pendulum; g = 9.81 m/s2acceleration due to gravity; l length of a pendulum.
Absolute error for indirect measurement of moment of inertia:
,
where δJ relative error for indirect measurement of moment of inertia:
,
here , , relative errors for mass, length and period of the pendulum; Δm, Δl, ΔT absolute errors for mass, length and period of the pendulum.
4. Theoretically determined a value of moment of inertia:
.
5. Average value of equivalent length of the pendulum:
.
6) Table of measurements
m =kg; Δm =0,001 kg; l =m; Δl = 0,001 m;
Ή
ti, s
Ti, s
ΔTi, s
(ΔTi)2, s2
1.
2.
3.
4.
5.
average value <T>=
7) Data processing:
8) Final results:
1. T=( <T> ± ΔT)α = ( ± )0.95 s, = %.
2. x(t)= ×cos( t + ) m;
3. JEXP = (< J> ± ΔJ)α= ( ± )0.95 kg·m2, = %;
4. JTHEOR =kg·m2;
5. l eq= m.
9)Conclusion:
(Compare moment of inertia defined experimentally by formula (22) with that of defined by theoretical calculation by formula (23)).